Question 1 - Jee advanced Math 2022 P1 Questions with Solutions
Considering only the principal values of the inverse trigonometric function, the value of \(\frac{3}{2} \cos^{-1}{\sqrt{\frac{2}{2+\pi^{2}}}} + \frac{1}{4}\sin^{-1}{\frac{2\sqrt{2}\pi}{2 + \pi^{2}}} + \tan^{-1}{\frac{\sqrt{2}}{\pi}}\) is ____. Sol : Convert \(\cos^{-1}\) and \(\sin^{-1}\) terms into \(\tan^{-1}\). To Convert \(\cos^{-1}\) term into \(\tan^{-1}\) : Let \(t = \cos^{-1}{\sqrt{\frac{2}{2+\pi^{2}}}} = \cos^{-1}{\frac{\sqrt{2}}{\sqrt{2+\pi^{2}}}}\) …(1) \(\implies\)\(\cos{t} = \frac{\sqrt{2}}{\sqrt{2+\pi^{2}}}\) Use right angle triangle to determine ‘\(\tan{t}\)’. Consider a right triangle as shown above, with side adjacent to angle ‘t’ equal to \(\sqrt{2}\), and hypotenuse equal to \(\sqrt{2+\pi^{2}}\). Using Pythagoras’ theorem, side opposite to ‘t’ \(= \sqrt{2+\pi^{2} - 2} = \pi\) Hence, \(\sin{t} = \frac{\pi}{\sqrt{2+\pi^{2}}}\) And, \(\tan{t} = \frac{\sin{t}}{\cos{t}}\) \( = \fra...